The average density of the Earth is [ $g$ is acceleration due to gravity]:

Given below are two statements:
Statement $I:$ Rotation of the earth shows effect on the value of acceleration due to gravity $(g)$.
Statement $II:$ The effect of rotation of the earth on the value of $g$ at the equator is minimum and that at the pole is maximum.
In the light of the above statements,choose the correct answer from the options given below.

The depth $d$ at which the value of acceleration due to gravity becomes $\frac{1}{n}$ times the value at the surface is [$R =$ radius of the earth].

An astronaut on a strange planet finds that the acceleration due to gravity is twice that on the surface of the Earth. Which of the following could explain this?

What is the height from the surface of earth,where acceleration due to gravity will be $\frac{1}{4}$ of that of the earth (in $km$)? $(R_E = 6400 \ km)$

Write the equation of acceleration due to gravity at a height $h$ from the surface of the Earth,where $h << R_e$.